Say "maths class" five times as fast as you can and you'll find out why we simplified it.
Tom
"... say "Maths Class" five times . . . "
... reminds me of writing out lines at school only that would be five hundred times ..... " I must not (insert many an evil deed)"
:)
Well I measured the distance and it is 1.625" (rounded down a little). However, the v isn't 90°, so the vertical distance is 0.875". Therefore, I calculate the hypotenuse as being 1.8456029", which gives me a diameter of 3.692" (approx 93.75mm).
(04-08-2014, 08:30 AM)Mayhem Wrote: [ -> ]Well I measured the distance and it is 1.625" (rounded down a little). However, the v isn't 90°, so the vertical distance is 0.875". Therefore, I calculate the hypotenuse as being 1.8456029", which gives me a diameter of 3.692" (approx 93.75mm).
Mayhem,
The distance 1.625" you measured is that the distance between the vee at the top, or is it the distance between the vee at the top divided by 2?
DaveH
Bugger! I forgot to divide by 2